openttd-mini: comparison ai

equal deleted inserted replaced

-:66d2d61e77a8
+:fff56bbc3606
 		if (p->ainew.from_type == AI_CITY && p->ainew.tbt == AI_BUS) {
 			int max_cargo = DEREF_TOWN(p->ainew.from_ic)->max_pass + DEREF_TOWN(p->ainew.temp)->max_pass;
 			max_cargo -= DEREF_TOWN(p->ainew.from_ic)->act_pass + DEREF_TOWN(p->ainew.temp)->act_pass;
 			// max_cargo is now the amount of cargo we can move between the two cities
-			// If it is more then the distance, we allow it
+			// If it is more than the distance, we allow it
 			if (GetTileDist(DEREF_TOWN(p->ainew.from_ic)->xy, DEREF_TOWN(p->ainew.temp)->xy) <= max_cargo * AI_LOCATEROUTE_BUS_CARGO_DISTANCE) {
 				// We found a good city/industry, save the data of it
 				p->ainew.to_ic = p->ainew.temp;
 				p->ainew.state = AI_STATE_FIND_STATION;
 	// Don't do an attempt if we are trying the same id as the last time...
 	if (p->ainew.last_id == p->ainew.temp) return;
 	p->ainew.last_id = p->ainew.temp;
 }
-// Check if there are not more then a certain amount of vehicles pointed to a certain
+// Check if there are not more than a certain amount of vehicles pointed to a certain
 //  station. This to prevent 10 busses going to one station, which gives... problems ;)
 static bool AiNew_CheckVehicleStation(Player *p, Station *st) {
 	int count = 0;
 	Vehicle *v;
 	return;
 }
 // First, we are going to look at the stations that already exist inside the city
 //  If there is enough cargo left in the station, we take that station
-//  If that is not possible, and there are more then 2 stations in the city, abort
+//  If that is not possible, and there are more than 2 stations in the city, abort
 	i = AiNew_PickVehicle(p);
 	// Euhmz, this should not happen _EVER_
 	// Quit finding a route...
 	if (i == -1) { p->ainew.state = AI_STATE_NOTHING; return; }
 			}
 		}
 	}
 	// We are going to add a new station...
 	if (new_tile == 0) count++;
-	// No more then 2 stations allowed in a city
+	// No more than 2 stations allowed in a city
 	//  This is because only the best 2 stations of one cargo do get any cargo
 	if (count > 2) {
 		p->ainew.state = AI_STATE_NOTHING;
 		return;
 	}
 	if (p->ainew.from_deliver)
 		max_cargo = DEREF_INDUSTRY(p->ainew.from_ic)->total_production[0];
 	else
 		max_cargo = DEREF_INDUSTRY(p->ainew.to_ic)->total_production[0];
-	// This is because moving 60% is more then we can dream of!
+	// This is because moving 60% is more than we can dream of!
 	max_cargo *= 0.6;
 	// We want all the cargo to be gone in a month.. so, we know the cargo it delivers
 	//  we know what the vehicle takes with him, and we know the time it takes him
 	//  to get back here.. now let's do some math!
 			amount = 2 * length * max_cargo / tiles_a_day / 30 / RoadVehInfo(i)->capacity;
 return;
 } else {
 p->ainew.veh_main_id = p->ainew.veh_id;
 }
-// When more then 1 vehicle, we send them to different directions
+// When more than 1 vehicle, we send them to different directions
 		idx = 0;
 		order.type = OT_GOTO_STATION;
 		order.flags = 0;
 		order.station = _map2[p->ainew.from_tile];
 if (p->ainew.tbt == AI_TRUCK && p->ainew.from_deliver)
 	// When a vehicle is under the 6 months, we don't check for anything
 	if (v->age < 180) return;
 	// When a vehicle is older then 1 year, it should make money...
 	if (v->age > 360) {
-		// If both years together are not more then AI_MINIMUM_ROUTE_PROFIT,
+		// If both years together are not more than AI_MINIMUM_ROUTE_PROFIT,
 		//  it is not worth the line I guess...
 		if (v->profit_last_year + v->profit_this_year < AI_MINIMUM_ROUTE_PROFIT ||
 			(v->reliability * 100 >> 16) < 40) {
 			// There is a possibility that the route is fucked up...
 			if (v->cargo_days > AI_VEHICLE_LOST_DAYS) {

changeset 826	fff56bbc3606
parent 679	04ca2cd69420
child 900	27eb21ced433